acceleration of a ball thrown vertically upwards during upward movement, Time taken by the ball to reach the maximum height during its upward movement, maximum height reached during upward movement, at the highest point the velocity becomes zero. In other words, during upward movement, the ball is moving with retardation. . downwards as the ball is now ready to free fall. You can specify conditions of storing and accessing cookies in your browser. If the mass of a 200 N object is cut in half, what would happen to its weight in Newtons?, how does current flow in a closed circuit, a bus traveling with a speed of 54 km/h has a kinetic energy of 2x10^6 j. what is the mass of the bus, i just what to talk.. angles are measured from the normal, which is perpendicular to the surface, curved surfaces don't matter. Since the angles are measured from the normal, which is perpendicular to the surface, curved surfaces don't matter. Differently, we can say that the KE availed by the thrown object gets corroded under the negative influence of oppositely directing gravity (Gravitational force due to earth). What are the forces acting on a ball thrown upwards? As height rises, velocity falls which results in a reduction of KE and a corresponding rise in PE. 4. Lets discuss thephases of this traversal and motion with some formula and examples. A ball is thrown vertically upwards from the ground with an initial velocity of 50m/s. (ii)V^2 = U^2 2gH..(iii)During downward movement:V = U + gt(iv)H =Ut + (1/2) g t^2. placed 20 cm away from the mirror. Solution Step 1: Given Data The initial velocity of the ball u = 49 m s - 1 The final velocity of the ball v = 0 Let the acceleration due to gravity be g = 9. An increase in the number of carbon atoms in hydrogens decreases the boiling point. And during the downward movement, the final velocity is v3. TRUE OR FALSE. A ball is thrown vertically upward with a velocity of 20 m/s. 5. Answer: 1) Let the initial velocity of the ball be = u. rajsri1975p85ug8 rajsri1975p85ug8 03.05.2018 Science Secondary School answered A ball is thrown vertically upwards 2 See answers Advertisement The site owner may have set restrictions that prevent you from accessing the site. Concept used: 1) Velocity of a body thrown upwards at the highest point is 0 m/s. Equations for uniformly accelerated motion-. The distance s (in feet) of the ball from the ground after t seconds is s(t)=80 t-16 t^2Watch the full video at:https://www.numerade.com/questions/a-ball-is-thrown-vertically-upward-with-an-initial-velocity-of-80-feet-per-second-the-distance-s-in-/Never get lost on homework again. Also, find the height of this highest point. Numerade is a STEM learning website and app with the worlds largest STEM video library.Join today and access millions of expert-created videos, each one skillfully crafted to teach you how to solve tough problems step-by-step.Join Numerade today at:https://www.numerade.com/signup/ A ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity of 80 feet per second. 2 See answers Advertisement driamsick The instantaneous speed that its maximum height is zero.The reason is that the ball can only have potential energy while it is ascending vertically upward at the top of the height where the ball was thrown the speed decreases until it reached the peak and turn the speed into zero. length 15 cm. A ball is thrown vertically upward and it reaches a maximum height of 90 m. g = 9.8 m/s To Find : - The velocity with which it was thrown The height reached by the ball after 7s. As a result of the EUs General Data Protection Regulation (GDPR). Its distance s from a fixed point varies with time t according to the following graph. 2 See answers Advertisement lilmaj10 The entire time the ball is in the air, its acceleration is 9.8 m/s2 down provided this occurs on the surface of the Earth. It increases. It can be proved that the time for the downward movement or the time taken by the ball to fall from the highest point and reach the ground is same as the time required for the upward movement =v1/g, Lets prove it here mathematically:(see the diagram above for downward movement), so, T = v3/g = v1/g (from equation v above) . Answer- The above question is from the chapter 'Kinematics'. Its value is generally taken as 9.8 m/s^2. (vi), So Time for downward movement (T) = Time for upward movement ( t ) = v1/g, That means, time for downward travel = time of upward travel, So (from equation ii and vi) for a vertically thrown object the total time taken for its upward and downward movements= t + T=2v1/g . What is the velocity of the ball just before touching the ground? **Those who are aware of escape velocity, you can read a post on it here: Escape Velocity. b A converging mirror forms a real image of height 4 cm, of an object of height 1 cm Then ball will fall down ward with increasing speed. Here its the kinetic energy of the object which is expressed as 0.5 m V^2. Since the. Every weekend, he visits his plants to remove weeds. A ball is thrown vertically upwards with a velocity of 49 m s - 1. (vii), Say a ballis thrown vertically upward with 98 m/s velocity, So v1 = 98 m/s. And the acceleration working on the ball at this point is the acceleration due to gravity (g) and this time its considered positive i.e. And finally, the velocity of the ball becomes zero at a height. 2. And one important point, during the downward fall the magnitude of the velocity of the ball just before touching the ground would be the same as the magnitude of the velocity with which it was thrown upwards (v1 here). its velocity becomes zero at that height. 3. Its value is approximately 9.8 m/s^2 and its direction would be downwards towards the center of the earth. Solution : - It is given that the maximum height achieved by the ball is 90 m from initial velocity u , Maximum Height = u / 2g 90 2g = u 180 9.8 = u Plastics such as polyethylene, polypropylene, and polystyrene are hydrocarbons. Upward movement and then a downward movement of a ball when a ball is thrown vertically upward this is what we will discuss here and as well as we will derive the equations of the vertical motion. 3. During downward movement balls direction is the same as that of gravity and as a result, the ball comes down with acceleration and reaches the ground. Get access to this page and additional benefits: Course Hero is not sponsored or endorsed by any college or university. What is the difference between Instantaneous Speed and Instantaneous Velocity. What are the important formulas or pointers related to vertical motion? Butanol is an example of a hydrocarbon., how many mole are there in 200.00g of chlorine , What is the focal length of a converging lens if an object placed 12 cm makes a virtual image 28 cm away from the lens? During this downward displacement, the initial velocity is equal to the final velocity of the upward movement i.e. Law of Reflection the Law of reflection would still hold even off a curved surface. H = U2/(2g) = (492)/(2 x 9.8)=122.5 m T = U/g = 49/9.8 = 5 secif(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[250,250],'physicsteacher_in-large-mobile-banner-2','ezslot_6',151,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-large-mobile-banner-2-0'); H = U2/(2g) = (202)/(2 x 9.8)=20.4 m T = U/g = 20/9.8 = 2.04 sec, The time taken to reach its max height = 6/2 = 3 secWe know, T = U/g or, U = gT U= 10 x 3 m/s = 30 m/s. (Acceleration due to gravity = 10 m/s) 2) A stone is thrown down vertically from the top of a tower with initial velocity of 10 m/s. A ball is thrown from the top of a tower in vertically upward direction. The velocity of the object at maximum height is 0 m/s (it stops before it falls back to the ground). Originally Answered: A ball is thrown vertically upwards from the ground with an initial velocity of 50m/s. Note that the acceleration can be either 9.8 m/s2 or -9.8 m/s2. The velocity of the at maximum height is 0 m/s at the highest point since, when you throw a ball upward, it decelerates and stops momentarily at the highest point before it falls back to the ground. (ii) The total time it takes to return to the surface of the earth. An object 4 cm in size is placed at a distance of 25 cm from a concave mirror of focal This velocity is attained by the vertically falling ball just before touching the ground.if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[320,50],'physicsteacher_in-narrow-sky-2','ezslot_22',158,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-narrow-sky-2-0');if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[320,50],'physicsteacher_in-narrow-sky-2','ezslot_23',158,'0','1'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-narrow-sky-2-0_1'); .narrow-sky-2-multi-158{border:none !important;display:block !important;float:none !important;line-height:0px;margin-bottom:7px !important;margin-left:auto !important;margin-right:auto !important;margin-top:7px !important;max-width:100% !important;min-height:50px;padding:0;text-align:center !important;}. Hard Solution Verified by Toppr Initially ball will go up with decreasing speed. What is the total time spent by the ball on the air (g=100m/S)? the Gravitational Pull of the earth towards the center of it. When a ball is thrown vertically upward it starts its vertical motion with an initial velocity. Write ORGANIC if the statement is correct and COMPOUND if it is incorrect. No tracking or performance measurement cookies were served with this page. A ball is thrown vertically upwards. Calculate the velocity with which the stone strikes the ground and the height of the tower. Requested URL: byjus.com/question-answer/a-ball-is-thrown-vertically-upwards-with-a-velocity-of-49-ms-calculate-1-the-maximum-height-to-which-it-rises-2-the-total-time-it-takes-to-return-to-the-surface-of-the-earth/, User-Agent: Mozilla/5.0 (iPhone; CPU iPhone OS 14_7_1 like Mac OS X) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/14.1.2 Mobile/15E148 Safari/604.1. v3 = v1.(v). Numerade is a STEM learning website and app with the worlds largest STEM video library.Join today and access millions of expert-created videos, each one skillfully crafted to teach you how to solve tough problems step-by-step.Join Numerade today at:https://www.numerade.com/signup/quadratic inequalities List of formulas related to a ball thrown vertically upward [formula set]. Derive the equation of the Time taken by the ball to reach the maximum height during its upward movement. Calculate the maximum height to which it rises. After some time, it returns to the thrower. what is its instantaneous speed at its maximum height, Mang Erning is a farmer. i look good;) Given question: 1) A body thrown vertically upwards reaches the highest point of its path in 2 s. Find the initial velocity with which the ball is thrown. if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[250,250],'physicsteacher_in-mobile-leaderboard-2','ezslot_17',177,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-mobile-leaderboard-2-0');As v2=0, (at the highest point the velocity becomes zero), so we can rewrite equation iii as: or H= v12/2g (equation of maximum height) . Why an object thrown upwards comes down after reaching a point? It strikes the ground after 2 seconds. This is basis of curved mirrors such as concave. A ball is thrown vertically upwards with a velocity of 49m/s calculate maximum height and time taken to reach maximum height. What is the acceleration of a ball thrown vertically upwards during upward movement? Physics College answered A ball is thrown vertically upward. As said above, this acceleration is nothing but the acceleration due to gravitycaused by gravitational pull or force exerted by the earth on the ball. 1. 5) Total time taken for upward and downward movement = 10 sec + 10 sec = 20 sec.if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physicsteacher_in-portrait-1','ezslot_28',161,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-portrait-1-0'); 6) Velocity just before touching the ground=same as initial velocity of throwing = 98 m/s, Try to solve a few numerical problems? T-T jk i don't. The important formulas and pointers for vertical motion include 1> the maximum height reached, 2> time required for up & down movement, 3> acceleration of the ball at different points, 4> the velocity of the ball at different instances, 5> forces acting on the ball, 6> formula or equation of vertical motion 7> Kinetic energy and potential energy of the ball in a vertical motionif(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[320,50],'physicsteacher_in-box-4','ezslot_2',148,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-box-4-0'); We will find all these in this post. What are the velocity and acceleration of the ball when it reaches the highest point? (v)V^2 = U^2 + 2gH..(vi), If a ball is thrown vertically upwards with an initial velocity V0 then here is a set of formula for your quick reference.1) Maximum height reached = H = V02 / (2 g) 2) Velocity at the highest point = 03) Time for upward movement = V0 /g4) Time for downward movement = V0 /g 5) Total time of travel in air = (2 V0 )/g 6) Acceleration of the ball = acceleration due to gravity (g) acting downwards, towards the center of earth [ignoring air resistance]7) Forces acting on the ball = Gravity (gravitational force exerted by the earth)[ignoring air resistance]. The object stops at maximum height due to deceleration brought by gravity. its velocity becomes zero at that height. 4. 5. When a ball is thrown vertically upward it starts its vertical motion with an initial velocity. What is the acceleration of a ball thrown vertically upwards during its downward movement? As this acceleration due to gravity (g) is working opposite to the upward velocity we have to use a negative sign in the formula below, used for the upward movement of the ball. We have to find out the expression of this v3. Draw the velocity-time graph and speed-time graph. The distance s (in feet) of the ball from the ground after t seconds is s(. Find out the formula of the time period for the downward movement when a ball is thrown vertically upward, how acceleration due to gravity varies with height and depth, Vertical motion numerical AP Physics, JEE, NEET, etc, Projectile motion Derivation of equations for class 11 | Parabolic trajectory, Maximum height, flight time, Horizontal Range, Variation of g with height and depth how g changes with height and depth, Terminal Velocity, Free Fall, & Drag force. You can specify conditions of storing and accessing cookies in your browser, A ball is thrown vertically upward. , ). The acceleration of the ball would be equal to the acceleration due to gravitycaused by gravitational pull or force exerted by the earth on the ball. Now from the Law of conversation of energy, we can say this rise in PE is happening at the cost of some form of energy being transformed. derive the equations of the vertical motion. What is the focal And we know that v2=0. if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physicsteacher_in-leader-2','ezslot_9',154,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-leader-2-0');The height where the velocity becomes zero which is the maximum height the ball went upward, say is H. And for this upward movement, the final velocity v2 is 0 because the ball has stopped at the end of this upward traversal. The acceleration is negative because this acceleration is directing downwards while the ball is moving upward.And because of this negative acceleration, the velocity of the ball is gradually decreasing. Its pretty evident that after the upward throw, the velocity of the ball gradually decreases i.e. At that point, velocity becomes zero. Derive the formula for the maximum height reached during upward movement when a ball is thrown vertically upward? (b) After how many seconds will the ball pass the top of the building on its way down?Watch the full video at:https://www.numerade.com/questions/a-ball-is-thrown-vertically-upward-from-the-top-of-a-building-96-feet-tall-with-an-initial-velocity-/Never get lost on homework again. 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So we can say thatduring the downward fall the magnitude of the velocity of the ball just before touching the ground would be same as the magnitude of the velocity with which it was thrown upwards (v1 here). Mass and Weight are they the same or different? Velocity at a point \( h \) meter below the point of\( \mathrm{P} \) projection is t. y (t) = Vo t - 1/2 g t^2 What is its acceleration right before it hits the earth? The entire time the ball is in the air, its acceleration is 9.8 m/s2 down provided this occurs on the surface of the Earth. Distance- It is the path length transversed by an object. 2) The time taken to reach the highest point = v1/g = 98 / 9.8 second = 10 second, 4) The time taken to reach the ground while falling from the highest point =v1/g = 98 / 9.8 second = 10 second. if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[250,250],'physicsteacher_in-leader-3','ezslot_10',174,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-leader-3-0');In all the above discussions, we have considered Air Resistance as negligible. length of the mirror. Let the height of the highest point be h. Using third equation of motion, v - u = 2ah, we get, 2) Initial velocity of the stone (u) = 10 m/s. The influence is negative because gravity is pulling downwards while the ball is trying to move upwards. The angle of incidence is the angle,created by the incident ray with the, Mississippi Department of Child Protection Services, Survey of Exceptionalities of Children & Youth, Access to our library of course-specific study resources, Up to 40 questions to ask our expert tutors, Unlimited access to our textbook solutions and explanations. When an object is thrown with certain initial velocity (say V), it gains a Kinetic energy at that moment of throwing. A ball is thrown vertically upwards. A stone falls towards the earth but the opposite is not observed-why? The distance s (in feet) of the ba. (PE = mgh where h is the height). This happens because Potential Energy (PE) is directly proportional to the height of the object. (Acceleration due to gravity = 10 m/s). Calculate velocity of projection of the ball. v2. And the maximum height H reached is obtained from the formula: v22=v12-2gH ( under negative acceleration) (iii). All hydrocarbons contain only carbon and hydrogen. We are not permitting internet traffic to Byjus website from countries within European Union at this time. What is the equation for object thrown upward? Their leaves have B. better taste A. bad smell C. hair-like structure D. thorns, III. if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[320,100],'physicsteacher_in-box-3','ezslot_7',647,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-box-3-0');Last updated on April 16th, 2021 at 12:19 pm. You can specify conditions of storing and accessing cookies in your browser. This is an Expert-Verified Answer 6 people found it helpful it returns 6s later. (ignoring air resistance), As the ball reaches the maximum height now it starts its free-fall towards the earth. A ball is thrown vertically upward. Try the link below.Vertical motion numerical AP Physics, JEE, NEET, etc. its following the same direction of the acceleration due to gravity (g). A ball is thrown vertically upwards with a velocity of 49 m/s. 2) A stone is thrown down vertically from the top of a tower with initial velocity of 10 m/s. A ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity of 80 feet per second. Last month, he planted his field with sugarcane and corn. The force applied on it is again the gravity and this time its having a positive acceleration i.e. Anupam M (NIT graduate) is the founder-blogger of this site. Displacement- It is the shortest distance between the initial and final point. Universal Law of Gravitation & Derivation of Gravitational Force formula. So Lets start with the fundamentals of vertical motion Kinematics. . This is basis of curved mirrors such as concave and convex Brainly User In a plane mirror,the angle of incidence and angle of reflection are equal. 1. Just summing up the answer here though we have already gone through this in the section above. A.-10.cm B.-8.4 cm C. 8.4 cm D We know the value of g in SI is 9.8 m/second square.if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physicsteacher_in-mobile-leaderboard-1','ezslot_16',173,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-mobile-leaderboard-1-0'); As v2=0, (at the highest point the velocity becomes zero), then we can write the previous equation as follows: if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physicsteacher_in-leader-4','ezslot_15',176,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-leader-4-0');So from equation (ii), the time taken by the ball to reach the maximum height is expressed as= (Initial Velocity with which the ball is thrown vertically upwards) / (acceleration due to gravity)..(iii). Also, we have to find out the time taken (say T) for this downward fall. He uses shirts with long sleeves so that his skin won't brushes against the leaves of his plant. The velocity at the highest point is zero as the ball momentarily halts there before starting its downward movement. The distance s (in feet) of the ball from the ground after t seconds is s=96+80 t-16 t^2 (a) After how many seconds does the ball strike the ground? In a plane mirror,the angle of incidence and angle of reflection are equal. , ates the soil by means of plow. Read more here. Then again it starts falling downwards vertically and this time its velocity increases gradually under the influence of gravity. And then starts falling towards the earths surface. What is the total time spent by the ball on the air (g=10m/s)? Calculate the image distance. Bending of light round the corners is called _________________of light. Taking upward direction as (+)ve. A ball is thrown vertically upwards. At one point KE becomes zero. Find the position, nature and height of the image 9. And Yes. Find an answer to your question a ball is thrown vertically upwards. Add your answer and earn points. calculate maximum height and time taken to reach maximum height. As it moves upwards vertically its velocity reduces gradually under the influence of earths gravity working towards the opposite direction of the balls motion. Using 1st equation of motion, v = u + at, we get. if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[320,50],'physicsteacher_in-netboard-2','ezslot_26',179,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-netboard-2-0');if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[320,50],'physicsteacher_in-netboard-2','ezslot_27',179,'0','1'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-netboard-2-0_1'); .netboard-2-multi-179{border:none !important;display:block !important;float:none !important;line-height:0px;margin-bottom:7px !important;margin-left:auto !important;margin-right:auto !important;margin-top:7px !important;max-width:100% !important;min-height:50px;padding:0;text-align:center !important;}Therefore if a ballis thrown vertically upwards with 98 m/s velocity, the maximum height reached by it would be = (98 x98 )/(2 x 9.8) meter = 490 meters. At highest point velocity will be zero. Velocity- It is the displacement per unit time. This site is using cookies under cookie policy . Considering the Air resistance or Drag force negligible, the only force acting on the ball is Gravity i.e. Say a ball is thrown vertically upward with some velocity say v1, which we will consider as the initial velocity for the upward path. the Law of reflection would still hold even off a curved surface. So just for example, if a ball is thrown vertically upwards with 98 m/s velocity, then to reach the maximum height it will take = 98/9.8 =10 seconds. The velocity with which it was thrown is: Upward movement of the ballwhen a ball is thrown vertically upward some important points. Calculate (i) The maximum height to which it rises. After some time when the entire KE gets nullified, the ball stops. For more information, kindly visit the link below: This site is using cookies under cookie policy . It is a vector quantity as it possesses magnitude and direction. Hope you have enjoyed this post. In other words, during upward movement, the ball is moving with retardation. We will prove it mathematically here: Here while falling vertically downward, the ball falls the same height H (here H = v12/2g, as given in equation iv). 2. what is its instantaneous speed at its maximum height See answer Advertisement Babzki #BrainlyFast Answer: The velocity of the at maximum height is 0 m/s at the highest point since, when you throw a ball upward, it decelerates and stops momentarily at the highest point before it falls back to the ground. Acceleration due to gravity (a) = -10 m/s. Now you may share it as much as possible using the social media buttons on the page. Acceleration- It is the rate of change of velocity. See herehow acceleration due to gravity varies with height and depth wrt the surface of the earth. Let the final velocity of the stone be v. Acceleration due to gravity (a) = 10 m/s, This site is using cookies under cookie policy . Also, find the height of this highest point. (A) 10 m/s (B) 20 m/s (C) 30 m/s (D) 50 m/s User is waiting for your help. He also cultiv What is its acceleration right before it hits the earth? How do these plants protect themselves from enemies? After a certain time period t,the ball reaches a height beyond which it cant move upwards anymore and stops there i.e. 8 m s - 2 Let the maximum height be h. Step 2: Formula used Negative acceleration is called retardation. Because it hasn't hit the ground yet. (iv). . acceleration of a ball thrown vertically upwards during its downward movement, during the downward fall the magnitude of the, same as the time required for the upward movement, Total time required for the upward and downward movement, So (from equation ii and vi) for a vertically thrown object the, Vertical motion when a ball is thrown vertically upward with derivation of equations, Numerical problem - a ball thrown vertically upwards, Draw the Displacement-time graph of a ball thrown vertically, The difference between a distance-time graph and a, Derivation of the Equations of Motion | deriving 'suvat, Kinematics equations - quick reckoner of motion equations, Derivation of Gravitational potential energy equations. As it moves upwards vertically its velocity reduces gradually under the influence of earth's gravity working towards the opposite direction of the ball's motion. After this, the ball starts falling downwards. The motion equations applicable for an object thrown upward are:During upward movement:V = U gt(i)H =Ut (1/2) g t^2. Given question: 1) A body thrown vertically upwards reaches the highest point of its path in 2 s. Find the initial velocity with which the ball is thrown. What happens when a ball is thrown vertically upward? v32 = v22 + 2 g H = 0 + 2 g (v12/2g) = v12i.e. a negative acceleration was working on the ball. A ball is thrown vertically upward with an initial velocity of 80 feet per second. Note that the acceleration can be either 9.8 m/s2 or -9.8 m/s2. Most organic compounds are flammable (can easily bum Acceleration due to gravity going up is -9.8 m/s (decelerating), which means the velocity of the object going up decreases by 9.8 m/s every second and eventually the object will momentarily stops when it reaches it maximum height before if falls back to the ground. A ball is thrown vertically upward with an initial velocity of 80 feet per second. A ball is thrown vertically upward. 1) The maximum height reached by it would be = v12/2g=(98 x98 )/(2 x 9.8) meter = 490 meter. Medium Solution Verified by Toppr Given Initial velocity of ball, u=49 m/s Let the maximum height reached and time taken to reach that height be H and t respectively. This is called the highest point for an upward vertical movement. As it moves upwards from its initial position (wherefrom its thrown) and gains height, its potential energy rises.